Write a quadratic equation could some please help asap​

f(x) = x^2 + 3x + 2.

Step-by-step explanation:

The zeroes of the quadratic function are -1 and -2 so we can write it as:

f(x) = a(x + 1)(x + 2)    where  a is some constant.

Now, when x = 1,  f(x) = 6 so

6 = a(1+1)(1+2)

6 = a*2*3 = 6a

a = 1.

So the function is f(x) = (x + 1)(x + 2) = x^2 + 3x + 2.

answer: t=3

step-by-step explanation:

3/4 ÷ 3/4

step-by-step explanation:

basically divide any proper fraction with itself to fit the criteria.

so if we are using 3/4, then:

3/4 ÷ 3/4 = 1

so 1 is the quotient.

and the numerators for both these fractions is 3.   and if we divide the numerators:

3 ÷ 3 = 1

we see that quotient is equal to our original quotient as well.