If sin y° = s over 8 and tan y° = s over t, what is the value of sec y°? sec y° = 8s

sec y° = 8t

sec y° = 8 over t

sec y° = t over 8

The third choice:   8 over t.

Step-by-step explanation:

tan y = sin y / cos y

s/t = s/8 / cos y

cos y = s/8 /  s/t

= s/8 * t/s

= t/8

sec y = 1 / cos y

= 1 / t/8 = 8/t.

sec y° = 8/t

Step-by-step explanation:

Sin y°=s/8, tan y°=s/t=sin y°/cos y°

We sec y° = 1/cos y°

Thus, we can make a equation to solve the problem. s/t = (s/8)/cos y°

The answer of this equation is cos y°=t/8

Thus the answer is sec y° = 8/t

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet