Help please! brainiest to best answer! <3 Kayson is looking at two buildings, building A and building B, at an angle of elevation of 40°. Building A is 120 feet away, and building B is 60 feet away. Which building is taller and by approximately how many feet?

Building A; it is around 100.69 feet taller than building B
Building A; it is around 50.34 feet taller than building B
Building B; it is around 100.69 feet taller than building A
Building B; it is around 50.34 feet taller than building A

Hello! Here your answer!...

The buildind B is taller, by approximately 33.286 feet

Step-by-step explanation:

To find the height of the buildings, we can use the tangent relation of the angle of elevation. The opposite side is the height of the building, and the adjacent side is the distance to the building:

Using h_A to the height of building A and h_B to the height of building B, we have:

tan(59) = h_A / 40

1.6643 = h_A / 40

h_A = 66.572 feet

tan(59) = h_B / 60

1.6643 = h_B / 60

h_B = 99.858 feet

The buildind B is taller, by approximately (99.858 - 66.572) = 33.286 feet

Hope this helps!♥

Building A; it is around 50.34 feet taller than building B

Step-by-step explanation:

hope this help

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!

homozygous. one is homozygous, while two is heterozygous.