3m=5(m+3)-3 How do I solve it

Simplifying

3m = 5(m + 3) + -3

Reorder the terms:

3m = 5(3 + m) + -3

3m = (3 * 5 + m * 5) + -3

3m = (15 + 5m) + -3

Reorder the terms:

3m = 15 + -3 + 5m

Combine like terms: 15 + -3 = 12

3m = 12 + 5m

Solving

3m = 12 + 5m

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-5m' to each side of the equation.

3m + -5m = 12 + 5m + -5m

Combine like terms: 3m + -5m = -2m

-2m = 12 + 5m + -5m

Combine like terms: 5m + -5m = 0

-2m = 12 + 0

-2m = 12

Divide each side by '-2'.

m = -6

Simplifying

m = -6

m = -6

Step-by-step explanation:

First you distribute 5 into (m+3) so it would 5m + 15

The equation now would be:

3m = 5m + 15 - 3

3m = 5m + 12

3m - 5m = 5m -5m + 12

-2m = 12

-2m/-2 = 12/-2

m = -6

huh? im pretty sure it is in 199

step-by-step explanation:

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

the factor is 2

step-by-step explanation:

let f(x)=8(3^(x−2)+2)

to stretch a graph by 3, it would be 3f(x)

g(x) =3f(x)

g(x) = 3*(8(3^(x−2))+2)

g(x) = 24 (3^(x-2) )+6

x     −2     0     2     4     6

f(x) 1/64 1/16   1/4     1     4

1/64 * z * z = 1/16

i multiplies by z twice because it its 2 steps from -2 to 0

1/64 z^2 = 1/16

multiply by 64 to clear the fraction on the left side

1/4 * 64 z^2 =1/16 *64

z^2 = 4

take the square root of each side

sqrt(z^2) = ±sqrt(4)

z = ±2  

we are multiplying by 2 each time.