Use continuity to evaluate the limit. lim
x→9 16+√x/√16+x
Consider the intervals for which the numerator and the denominator are continuous.
The numerator 16+√x
is continuous on the interval Correct The denominator √16+x is continuous and nonzero on the interval

The interval for which the quotient is continuous is the intersection of the above intervals. Therefore, the quotient 16+√x/√16+x is continuous on the interval
Since x=9 is in the interval [0,∞) , then f is continuous at x=9 . Therefore, limx→9
16+√x/√16+x=f(9)=

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

its a trick question

step-by-step explanation:

dogs love water, just turn on the hose and it will run in circles chasing the water all day : )

the car was traveling 40 mph before it started skidding. ( 2 points ) 17. was the driver were her brakes working at 75% efficiency or better? ( 2 points ) yes 29.

step-by-step explanation: