PLS HELP WILL GIVE BRAINLIEST!! Identify this set of lines as parallel, perpendicular, or neither.

neither

Step-by-step explanation:

neither

Step-by-step explanation:

parallel lines have the same slope

perpendicular lines have the opposite of the reciprocal of the slope of the other line

The slope of the first line is 3 and the slope of the second line is -3.

If the lines were parallel, the slopes would be the same, so 3 = -3 which is not true, so they aren't parallel.

If the lines were perpendicular, the slope of the second line would be the opposite reciprocal of 3, or -1/3. -1/3 does not equal 3, so these lines are not perpendicular

6, 10

9, -13

12, -21

18, -23

step-by-step explanation:

you just add 6 to the x-coordinate and subtract 10 from the y-coordinate.

< xcy ≅ < xby

step-by-step explanation:

in δcax and δbax,

so, δcax ≅ δbax (side-angle-side or sas)

since δcax ≅ δbax, we can conclude < acx ≅ < abx

in δacy and δaby,

so, δacy ≅ δaby (side-angle-side or sas)

since δacy ≅ δaby, we can conclude < acy ≅ < aby

now,

< acy ≅ < aby

=> < acx + < xcy ≅ < abx + < xby

=> < acx + < xcy ≅ < acx + < xby   (since < acx ≅ < abx already proved above)

subtracting < acx from both sides, we get

< acx + < xcy -< acx ≅ < acx + < xby -< acx

cancelling out < acx and -< acx from both sides, we get

< xcy ≅ < xby (proved)