HELP?:)

5. X = 2, Y = 3

6. X = 3, Y = 8

Step-by-step explanation:

For 5, it is easier to use the substitution method to solve. Plug the Y equation into the Y value of the first equation and simplify.

-3x - 2(5x-7) = -12

-3x - 10x + 14 = -12

-13 = -26x

x = 2

Then, plug the X value into either equation.

y = 5(2) -7

y = 3

For 6, it is easier to use the elimination method to solve. Multiply the first equation by 2 in order to eliminate 4y.

10x - 4y = -2

x + 4y = 35

Add these equations and simplify.

11x = 33

x = 3

Then, plug the X value into either equation.

3 + 4y = 35

32 = 4y

y = 8

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

80x^8−68x^6+16^5−20x^4−4x^3+8x^2

hope i'm right lol