Can someone please help me and explain I’ll mark brainliest

Part (a)

Work Shown:

2(x-1) = 3(x+2)

2x-2 = 3x+6 distribute

2x = 3x+6+2 adding 2 to both sides

2x = 3x+8

2x-3x = 8 subtracting 3x from both sides

-x = 8

x = -8 multiply both sides by -1

Part (b)

Work Shown:

-4(2x-2) = 3(x+1)

-8x+8 = 3x+3 distribute

-8x = 3x+3-8 subtract 8 from both sides

-8x = 3x-5

-8x-3x = -5 ... subtract 3x from both sides

-11x = -5

x = -5/(-11) divide both sides by -11

x = 5/11

In decimal form, this is approximately equal to 5/11 = 0.4545

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.