Jace measured a line to be 14 inches long. If the actual length of the line is 13.1 inches, then what was the percent error of the measurement, to the
nearest tenth of a percent?

6.87022901%

Step-by-step explanation:

He measured 14 out of 13.1 inches. There is a difference of 0.9 inches when u subtract. He miscalculated by 0.9 out of 13.1. In a calculator you divide .9 by 13.1 you get 0.0687022901. Multiply by 100 to get the percent and round it to your desired decimal place.

$6.42

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752