Construct an isosceles triangle MNO, having its base MN = 50 mm and the sum of its altitude and one side = 60 mm.

answer: the common difference is -0.10

what is the approximate angle of acb if abc is 25cm and the length of segment bc is 15

step-by-step explanation:

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°