Radius of the circle is 20cm. there are two chords of lengths. 32cm, what will be the dis-
tance of these chords from
the centre of the circle?​

9514 1404 393

  12 cm

Step-by-step explanation:

The distance to the chord is the median of an isosceles right triangle with hypotenuse 20 and leg 16. This 5:4 ratio suggests the other leg of that right triangle would make the ratios 3 : 4 : 5, so is 12.

The chords are 12 cm from the center.

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You can, of course, use the Pythagorean theorem. If c is half the chord length and d is the distance to the chord, you have ...

  c² + d² = r²

  16² + d² = 20²

  d² = 400 -256 = 144

  d = √144 = 12 . . . . . cm

whats the question?

step-by-step explanation:

u = -(6/7)w

step-by-step explanation:

place all values with 'u' on one side of the equation.

4u + 8w = - 3u + 2w

4u + 3u = 2w - 8w

further simplify the equation by solving the addition and subtraction.

7u = - 6w

make 'u' the independent variable by placing its co-efficient on the right-hand side.

u = - (6/7)w