Please answer fast The half-life of carbon-14 is 5,730 years. Suppose a fossil is found with 30 percent as
much of its carbon-14 as compared to a living sample. How old is the fossil?

28,993 years
9,955 years
2,899 years
996 years

Step-by-step explanation:

0.5^(t/5730) = 0.30

2^(-t/5730) = 0.30

-t/5730 = log₂0.30

t = -5730 log₂0.30 ≈ 9953 years

histogram or dot plot?

step-by-step explanation:

the range is 19

step-by-step explanation:

the range is biggest number minus the smallest, so in this case it would be

41 - 22 = 19