∠ABC and ∠DBC are complementary angles. If m∠ABC=6x+13 and m∠DBC=4x−3 what is the value of x?

x = 8

Step-by-step explanation:

complementary means add to 90

6x + 13 + 4x - 3 = 90

10x + 10 = 90

10x = 80

x = 8

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."