Jennifer has one more nickel than she has dimes. If she has $1.25 how many of each type of coin does she have? (HELP IS APPRECIATED)

She has 9 nickels, and 8 dimes.

Step-by-step explanation:

We know that she has a total of $1.25. We know that a nickel is $0.05, and that a dime is $0.10.

9x$0.05=$0.45

8x$0.10=$0.80

9 nickels

8 dimes

Step-by-step explanation:

.05(n + 1) + .10n = 1.25

.05n + .05 + .10n = 1.25

.15n = 1.20

n = 1.2 / .15

n = 8

but there are 9 nickels because there is "one more nickel than dimes"

use substitution to solve each system of equations. y = x + 5 3x + y = 25 62/87,21 y = x + 5 3x + y = 25 substitute x + 5 for y in the second equation. substitute the solution for x into either equation to find y. the solution is (5, 10)

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