José is making frult-filled tart shells for a party. He has 80 raspberries and 48 blueberrles. The tarts will each have the same number of berrles. Raspberrles and blueberrles will not be in the same tart If he puts the
greatest possible number of fruits in each tart, how many tarts can he make?
When the greatest possible number of berrles Is In each tart, there are
tarts In total.

8

Step-by-step explanation:the GCF for 80 and 48 is 16 so divide 80 by 16 and you will get 5 and 48 by 16 and you’ll get 3 and when you and 5 and 3 you’ll get 8 as your answer.

then say something, tell them they won’t respect you if you don’t even have respect for your self sweetheart you need to lay it on them, all of it : )

hello from mrbilldoesmath!

answer:   (7x + 6y) ( 49x^2 - 42xy + 36y^2)

discussion:

in general, the factorization of a^3 + b^3 is

a^3 + b^ 3 = (a + b) ( a^2 - ab + b^2)

in our case note that 343 = 7^3 and 216 = 6^3 so the equation becomes:

343x^3 + 216y^3 = (7x)^3 + (6y)^3

if you think of a (above) as 7x and b as 6y the factorization becomes

343x^3 + 216y^3 =

((7x + 6y) (   (7x)^2 - 7x*6y + (6y)^2)   =

(7x + 6y) ( 49x^2 - 42xy + 36y^2)

you,

mrb

(a + b) (a^2 - a b + b^2)