A store manager combines 2 lb of trail mix that contains some cashew nuts with 30 lb of trail mix that is 20% cashews. The result is a trail mix that is 25% cashews. What is the concentration of cashews in the first mixture?

100%

Step-by-step explanation:

Let  p = percent of cashews in first mix

2p = lb. of cashews in first mix

30(.20) =  6 = lb. of cashews in second mix

32(.25) =  8 = lb. of cashews in the combined mix

So,

lb. of cashews in first mix +  lb. of cashews in second mix = lb. of cashews in the combined mix

2p + 6 = 8

2p = 2

p = 1 = 100%

100%

Step-by-step explanation:

I solved it and it was correct lol

constant acceleration- a

constant velocity- c

no velocity or acceleration- b

explanation:

for body moving with a constant acceleration, the rate of change of displacement changes over time. this is proven by the increasing gradient of the curve (a) against time.

a body that is moving at constant velocity covers equal distances over equal periods of time, thus the straight line with a constant gradient c.

a stationary body   covers no displacement as time elapses. thus the flat line with   zero gradient.

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.