The ratio of length and breadth of a rectangular playground is 3:2. There is a two meter wide jogging track along and outside the playground. The
total area of the track and the playground is 2816 sq. m. Find the length
and breadth of the playground,​

We know that the ratio of length and breadth of a rectangular playground is 3:2

Then if the length is L, and the breadth is B, we have the relationship:

L = (3/2)*B

Outside this playground, we have a jogging track of 2m, then if we also consider the jogging track the length and breadth are:

L' = L + 2m

B' = B + 2m

The area is the product between the area and the breadth, then the area is:

A = B'*L'

A = (L + 2m)*(B + 2m)

And remember that L = (3/2)*B

Then we get:

A =  ((3/2)*B + 2m)*(B + 2m)

And the area is 2816 m^2

Then we have:

A =  ((3/2)*B + 2m)*(B + 2m) = 2816 m^2

Now we can solve the equation:

((3/2)*B + 2m)*(B + 2m) = 2816 m^2

(3/2)*B^2 + 3m*B + 2m*B + 4m^2 = 2816 m^2

(3/2)*B^2 + 5m*B =  2816 m^2 - 4m^2 = 2812m^2

Then we can write:

(3/2)*B^2 + 5m*B -  2812m^2 = 0

We can solve this if we use Bhaskara's formula:

One solution is negative, so we can discard that one, then we only take the positive:

B = (-5m + 130m)/3 = 41.67m

And L = (3/2)*B

L = (3/2)*40.7m = 62.5m

The breadth is 41.67 meters and the length is 62.5 meters.

- (2, -7)

- lines r and s and lines t and u must be parallel