If the sides of a triangle are in the ratio 3:4:5, prove that it is
right-angled triangle​

hope this helps

Step-by-step explanation:

Let a , b , c are three sides of a triangle

a : b : c = 3 : 4 : 5

a = 3x ,

b = 4x ,

c = 5x

a² = 9x²

b² = 16x²,

c² = 25x².

c² = a² + b²

by the pythagorean theorem,

a , b , c forms a right angled Triangle.

yes it's a right angle triangle

Step-by-step explanation:

Given the sides are in the ratio 3:4:5.

Let ABC be the given triangle.

Let the sides be 3x,4x and hypotenuse be 5x.

According to Pythagoras theorem,

AC

2

=BC

2

+AB

2

BC

2

+AB

2

=(3x)

2

+(4x)

2

=9x

2

+16x

2

=25x

2

AC

2

=(5x)

2

=25x

2

AC

2

=BC

2

+AB

2

Hence ABC is a right angled triangle

1d

2b

3 false

4 d

5 3200sq,ft

80+60+y=180

then divide the difference between 60 and y and add it to 180

so x =180 +( (y-60)/2)

x equals 200

step-by-step explanation:

8

hi,

i'm 75% sure the answer is 1,1 to both lines.

have a great day