A ball is thrown in the air from the top of a building. Its height, in meters above ground, as a function of time, in seconds, is given by h(t) = -4.9t? + 16 + 13. How long does it take to reach maximum height? (Round your answer to three
decimal places.)

S=?

It takes 1.633 seconds for the ball to reach maximum height.

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

It's vertex is the point

In which

If a<0, the vertex is a maximum point, that is, the maximum value happens at , and it's value is

In this question:

We have that the height is given by:

So .

The maximum height happens at the instant of time:

It takes 1.633 seconds for the ball to reach maximum height.

i think 1: 2

step-by-step explanation:

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)