Can someone help me​

ADB=45

Step-by-step explanation:

we know that angles a, b, c, and d are right, or 90 degrees. We also know that the two lines in the center are bisectors, which cut a angle perfectly in half. we can now use this equation for thet:

90/2=<ADB

ADB=45

the quotient is 4x^2 - 27x + 167 with a remainder of -996

step-by-step explanation:

in synthetic division, use -6 as the divisor and use the coefficients {4, -3, 5, 6}:

-6     )   4     -3     5     6

                -24   162 -1002

          4   -27   167   -996

thus, the quotient is 4x^2 - 27x + 167 with a remainder of -996.

note:   your "4x°-3x+5x+6" is ambiguous / incomplete.   i had to assume that you meant '4x^3 - 3x^2 + 5x + 6."