There are 10 books on a shelf. How many different ways can the books be arranged?

Please help

Number of books =10

Total number of ways =10!

Given pair of books to be together considering them as one

total sets =9

Number of ways of arranging them =9!ways

Those two books can be arranged in 2!

Total ways that the pair of books is together 

⇒9×2

Number of ways that are not together 

⇒10−9×2

⇒9(10−2)

⇒8×9

I hope you understand please give brainliest

Step-by-step explanation:

We have a total of 10 books. If a particular pair of books must always be together, just tie these two books together and consider as a single book. Hence we can take total number of books as 9. These 9 books can be arranged in 9P9 =9!

a - base

b - exponent

so,