Solve the following system of equations using Substitution: Submit your answer as an ordered pair. 2x−3y=32x-3y=32x−3y=3 x=y+2x=y+2x=y+2

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  (3, 1)

Step-by-step explanation:

We assume you want the solution to the system ...

The second equation gives a nice expression for x, so we can use that in the first equation.

  2(y+2) -3y = 3 . . . . substitute for x in the first equation

  2y +4 -3y = 3 . . . . . eliminate parentheses

  -y = -1 . . . . . . . . . . . collect terms, subtract 4

  y = 1 . . . . . . . . . . . . multiply by -1

  x = 1 +2 = 3 . . . . . . substitute for y in the second equation

The solution is (x, y) = (3, 1).

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