A person invests 3000 dollars in a bank. The bank pays 6% interest compounded quarterly. To the nearest tenth of a year, how long must the person leave the money in the bank until it reaches 7700 dollars?

16 years approx

Step-by-step explanation:

Given data

P=$3000

r= 6%

A= $7700

t= ??

The compound interest formula is

A= P(1+r)^t

Calculate time, solve for t

t = ln(A/P) / r

substitute

t= ln(7700/3000)/0.06

t= ln(2.566)/0.06

t= 0.942/0.06

t= 15.7

The time is 16 years approx

answer: i don't understand. what are the options

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°