PLS I NEED HELP I ONLY HAVE 15 MINS I BEG YOU PLEASE!! :( In 1984 the average American used to eat 55.7 pounds of chicken. This was 2.8 pounds more than the 1982 average. By what percent did chicken consumption increase from 1982 to 1984?

To solve this, we need to use the z statistic. The formula for z score is:

z = (x – u) / s

where x is sample value = less than 90, u is the sample mean = 90.6, s is the standard deviation = 17.2

z = (90 – 90.6) / 17.2

z = -0.035

From the standard distribution tables:

P (z = -0.035) = 0.4860

Therefore there is about 48.60 % chance that it will be less than 90 pounds

answer: 1000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000000

step-by-step explanation:

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i graphed to on desmos.