The local ranger station tracked and tagged 2,844 adult female black bears in a national park. A random sample of 9 adult female black bears from those tagged had an average body weight of 203 pounds with standard deviation 25 pounds. Which of the following is a point estimate for the population mean weight of all female black bears that are tagged? a. 9
b. 25/√9
c. 25
d. 203
e. 2,844

203

Step-by-step explanation:

Sample size, n = 9

Mean weight, m = 203

Standard deviation = 25

Point estimate for the population mean weight of all black bears that are tagged `

The point estimate of the population mean ;

ΣX / n

Sum of sample / sample size ;

This is the mean value formula for the sample.

However, since it has been given in the question that, sample mean weight value = 203 ; then the point estimate of the population mean weight = 203

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation: