An entrepreneur is considering the purchase of a coin-operated laundry. The current owner claims that over the past 5 years, the average daily revenue was $675 with a standard deviation of $75. A sample of 30 days reveals a daily average revenue of $625. If you were to test the null hypothesis that the daily average revenue was $675 with a level of significance level of 0.01. Which test would you use and why? a. Z-test of a population mean.
b. T-test of population mean.
c. Z-test of population proportion.
d. t-test of a population proportion

a. Z-test of a population mean.

Step-by-step explanation:

The current owner claims that over the past 5 years, the average daily revenue was $675 with a standard deviation of $75.

This means that we have a large sample, which means that we can consider this to be the standard deviation for the population, which eliminates the t-test, leaving options a and c.

Population mean or proportion?

Mean, as a proportion is a value between 0 and 1, while average revenue may have lots of possible values. So the answer is given by option A.

answer: since the question is talking about growth you have to use the growth formula which is inital amount (1 + growth)^time

step-by-step explanation:

the intial amount is 1200, the growth is 4.8, and the time is 7. plug those numbers into the equation, also i think you have to change 4.8 into a percent. but, i have forgotton how to do that. if this is a online class go on to the lesson.

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right