Find an equation of line containing (3, -4) and having slope -2. if this line contains the points (a, 8) and (5, b) find a and b ​

a = -3

b = -8

Step-by-step explanation:

Equation for a line is:

y-coordinate = (slope * x-coordinate) + y-intercept

For (3, -4): -4 = (-2 * 3) + y-intercept

y-intercept = 2

Equation for all points on this line is:

y = -2*x + 2

For (a, 8): 8 = (-2 * a) + 2

For (5, b): b = (-2 * 5) + 2

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step-by-step explanation:

answer: (c) m∠qpo + (2x + 16)° = 180°

step-by-step explanation:

the opposite angles of a quadrilateral are supplementary.

so, ∠o + ∠q = 180°   and   ∠p + ∠r = 180°

since ∠r = 2x + 16°, we can use substitution as follows:

∠p + ∠r = 180°

∠p + (2x + 16)° = 180°