A weight of 6 lb stretches a spring a distance of 12 in. Find the constant k for the spring.

6 Ib

Step-by-step explanation: 12-6=6

Let F = the force (6 lbs) and x be the distance that the spring is stretched (12 inches).

F = kx

6 lb = k*(12 in.)

6/12 = k = 0.5 lb/in.

fa tha first one you gonna add y to both sides

it look like this

x-y+y=6+y

x=y+6

therefore your answer is

x =y+6

fa tha second one

you gonna flip tha equation

it gonna look like x-4y=y

then add 4 to both sides

it gonna look like tha

x-4 +4 =y +4

so therefore tha answer is x=y+4

step-by-step explanation:

sas (side angle side)

aa (angle angle)

sss(side side side)

sas find two sides with an angle in between

aa is finding two angles and the third will add up to 180

sss find all sides

step-by-step explanation: