A triangular flower bed with sides 11 ft, 13 ft and 17 ft is filled 2 feet deep with compost that has a density of 13.2 lbs/ft2. How much willthe compost weigh that fills this flower bed?

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↓Answer↓

The length of a Triangular flower bed is 11 ft. less than 3 times its width. The area of the bed is 20ft^2. Find the dimensions of the flower bed.

let width be x

three times width =3x

length = 3x-11

x(3x-11)=20

3x^2-11x-20=0

3x^2-15x+4x-20=0

3x(x-5)+4(x-5)=0

(3x+4)(x-5)=0

x=5 width

width is 5 feet

length = 3x-11

=3*5 -11

=4 feet length

Hope this helped ya!

☁floofy-cloud☁

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

answer: plz give a pic and answer choices so i can answer!

step-by-step explanation: