A company that manufactures video cameras produces a basic model and a deluxe model. Over the past year, 50% of the cameras sold have been of the basic model. Of those buying the basic model, 34% purchase an extended warranty, whereas 47% of all deluxe purchasers do so. If you learn that a randomly selected purchaser has an extended warranty, how likely is it that he or she has a basic model

0.4198 = 41.98% probability that he or she has a basic model

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

In which

P(B|A) is the probability of event B happening, given that A happened.

is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Extended warranty

Event B: Basic model

Probability of extended warranty:

34% of 50%(basic model)

47% of 100 - 50 = 50%(deluxe model). So

Intersection of events A and B:

34% of 50%(basic model with extended warranty). So

How likely is it that he or she has a basic model

0.4198 = 41.98% probability that he or she has a basic model

18

step-by-step explanation:

draw the shape and you will see that f and k are actually at adjacent vertices (points of the hexagon that are neighboring).   so find the distance between (1,2) and (4,2).   that is easy since (1,2) and (4,2) is just a vertical distance to count, which is 3.   it is a regular polygon which means all sides are congruent.   you have 6 sides (hexa) so multiply 6 by 3 to receive 18.

throw the computer

step-by-step explanation: