Write in point-slope form an equation of the line that passes through the given point and has the given slope.
(1, – 3); m = 4

y+3=4(x-1)

Step-by-step explanation:

y-y1=m(x-x1)

y-(-3)=4(x-1)

y+3=4(x-1)

4sqrt5

step-by-step explanation:

the base has dimensions of 8 x 4, so the diagonal is 64 + 16 square rooted or 4sqrt5.

f(x) has value 150 at x= 0

and 0 at x= 3

so d(f(x))/dt = slope = -150/3 = -50