The students at a high school collected $3,800 to buy stuffed animals to give to a children’s hospital. The students bought both stuffed bears and stuffed dogs. Each bear cost $7, and each dog cost $8. The students bought a total of 500 stuffed animals and spent all the money. How many stuffed dogs did the students buy? A. 200 B. 205 C. 295 D. 300​

D. 300

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Algebra I

Step-by-step explanation:

Step 1: Define Variables

Stuffed bears = b

Stuffed dogs = d

Step 2: Define Systems

$7b + $8d = $3800

b + d = 500

Step 3: Rewrite Systems

b + d = 500

Step 4: Redefine Systems

7b + 8d = 3800

-7b - 7d = -3500

Step 5: Solve for d

Elimination

Step 6: Define Answer

d = 300 means that the students bought 300 stuffed dogs.

D

Step-by-step explanation:

Remark

Let the stuffed bear = x

Let the stuffed dog = y

Equations

x + y = 500                   (1)

7x + 8y = 3800               (2)

Solution

There are two ways you could do this. You can use substitution or you could use multiplying equation 1 by either 7 or 8 to get rid of the x or y.

Multiply (1) by 7

7x + 7y = 3500             (3)       Write equation (2) below (3) and subtract

7x + 8y = 3800                        Subtract

    -y = - 300                            Multiply by - 1

     y = 300

Use the result for y to get x using equation 1

x + y = 500

x + 300 = 500                         Subtract 300

x = 500 - 300

x = 200

Stuffed bears = 200

Stuffed dogs   = 300

use this formula:

p(a\b) = p(a and b)/p(b).

take it from here.

y=1/4x-4

step-by-step explanation: