​​In the figure shown, \overset{\leftrightarrow }{CF} CF ↔ intersects \overset{\leftrightarrow }{AD} AD ↔ and \overset{\leftrightarrow }{EH} EH ↔ at points BB and FF, respectively. ​ ​ ​ ​Part A ​Given: \angle CBD\cong \angle BFE∠CBD≅∠BFE ​​Prove: \angle ABF\cong \angle BFE∠ABF≅∠BFE ​Select from the drop-down menus to support each line of the proof. ​ ​​Statement: \angle CBD\cong \angle BFE∠CBD≅∠BFE Reason: ​ Reflexive property of congruence ​ ​Statement : \angle CBD\cong \angle ABF∠CBD≅∠ABF Reason: Vertical angles are congruent ​ ​Statement: \angle ABF\cong \angle BFE∠ABF≅∠BFE Reason: Reflexive property of congruence ​ ​Part B Given: m\angle CBD=m\angle BFEm∠CBD=m∠BFE Prove: m\angle BFE+m\angle DBF=180^{\circ}m∠BFE+m∠DBF=180 ∘ Select from the drop-down menus to support each line of the proof. ​ ​Statement: m\angle CBD=m\angle BFEm∠CBD=m∠BFE Reason: ​ Angles that are adjacent are supplementary ​ ​Statement: m\angle CBD+m\angle DBF=180^{\circ}m∠CBD+m∠DBF=180 ∘ Reason: ​ Angles that form a linear pair are supplementary ​ ​Statement: m\angle BFE+m\angle DBF=180^{\circ}m∠BFE+m∠DBF=180 ∘ Reason: ​ Transitive property of equality