g A highway department is studying the relationship between traffic flow and speed. The following model has been hypothesized. where traffic flow in vehicles per hour vehicle speed in miles per hour The following data were collected during rush hour for six highways leading out of the city. Traffic Flow () Vehicle Speed () 1257 36 1329 45 1227 30 1336 50 1349 55 1124 25 a. Use the data to compute the coefficients of this estimated regression equation (to decimals). Enter negative value as negative number. (Create the variable first using Data/Transform

ŷ = 0.1286X - 123.2175 ;

r = 0.947

r² = 0.896

Step-by-step explanation:

Given the data:

Traffic Flow, X : Vehicke speed ;Y()

1257 36

1329 45

1227 30

1336 50

1349 55

1124 25

The estimated regression equation using a linear regression calculator based on the data given above is given thus:

ŷ = 0.1286X - 123.2175

Where ;

y = dependent variable (vehicle speed)

x = predictor variable (traffic flow)

Slope = 0.1286

Intercept = 123.2175

The correlation Coefficient, R, obtained using the correlation Coefficient calculator is 0.9465, This depicts a very strong positive relationship between traffic flow and vehicle speed.

The Coefficient of determination, R² which is the squared value of the correlation Coefficient = 0.9465² = 0.8958 gives the proportion of explained variance ; This means about 89.5% of variation in Vehicle speed can be explained by the regression line.

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

idk

step-by-step explanation: