Use the graph and table to write the equation that describes the line graphed. A 2-column table with 5 rows. Column 1 is labeled x with entries negative 2, negative 1, 0, 1, 2. Column 2 is labeled y with entries 1, 2, 3, 4, 5.

The equation of the line
Please help me :(

I believe it is x−y+3=0.

Step-by-step explanation:

y= mx + b

The equation of a line is written as , so if you plug in the numbers from the first two rows on the grid you get, = = 1

The y- intercept is -m·, plug in the number and its, b=1-(1)·(-2)=3

Finally, the equation of the line can be written in the form y=mx+b.

y=x+3.

The equation of the line in the slope-intercept form is y=x+3.

The equation of the line in the point-slope form is y−1=1(x+2).

The general equation of the line is x−y+3=0.

It’s D y=X+3

Step-by-step explanation:

probably .5

i can on others if necessary.

answer:   (s+1)(s+4)

step-by-step explanation:

factor s2+5s+4

s2+5s+4

=(s+1)(s+4)