Of the people who fished at Clearwater Park today, 81 had a fishing license, and 9 did not. Of the people who fished at Mountain View Park today, 60 had a license, and 40 did not. (No one fished at both parks.) Suppose that one fisher from each park is chosen at random. What is the probability that the fisher chosen from Clearwater had a license and the fisher chosen from Mountain View did not have a license? Do not round your answer.

9/25 = the probability that the fisher chosen from Clearwater had a license and the fisher chosen from Mountain View did not have a license

Step-by-step explanation:

There are 90 fishers at Clearwater and 100 fishers at Mountain View

The probability of a fisher at Clearwater had a license = 81/90 = 9/10

and the probability of a fisher at Mountain View

did not have a license = 40/100 = 2/5

the probability that the fisher chosen from Clearwater had a license and the fisher chosen from Mountain View did not have a license = 9/10(2/5) = 9/25

step-by-step explanation:

if x = 2 you have to find x to finish the problem

the answer is a

step-by-step explanation: