I need help on knowing whether this is a solvable equation. Along with reasons why. HELP IF YOU CAN :))

To check if x = 9 is the solution, we need to replace every x with 9 and simplify

(3+x)/4 = 3

(3+9)/4 = 3

12/4 = 3

3 = 3

We get the same thing on both sides, so the last equation is a true equation. This means that the first equation is a true equation when x = 9. Therefore, the solution x = 9 is confirmed.

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation:

c.

step-by-step explanation:

substitution for (0,1)

y=x^2+4x+1

1=0^2+4(x)0+1

1=0+4(x)0+1

1=4(x)0+1

1=0+1

1=1

substitution for (-3,-2)

y=x+1

-2=-3+1

-2=-2