2 consecutive integers such that 7 times the smaller is less than 6 times the greater. What are the greatest such intergers

The numbers are

22 and 23  to solve a problem like this, we need to read and define as we go. Let me explain. So we know that there are two consecutive integers. They can be

x and x+1

. Since their consecutive, one has to be 1

number higher (or lower) than the other. Ok, so first we need "seven times the larger"( 7x+1)

Next, we need to "minus three times the smaller" 7(x+1)−3x

Is equal to " 957(x+1)−3x=95

Alright! There's the equation, now we just need to solve for  x! First we are going to get everything on one side and distribute the 7=7x+7−3x−95=4x−88

Pull out a

=4(x−22)Now that we have two terms, we can set them both equal to

0 and solve.4≠0

This can never be true, lets move to the next term (x−22)=0x=

22 That's it! So your two consecutive numbers are

22

water molecules will move from the side of higher water concentration to the side of lower concentration until both solutions are isotonic. at this point, equilibrium is reached. in an isotonic solution, the flow of water in and out of the cell is happening at the same rate.

hope this < 3

7

step-by-step explanation: