When can we use the method of extracting the square root in solving the roots of quadratic equations?​

This is the “best” method whenever the quadratic equation only contains x2 terms.

The general approach is to collect all x2 terms on one side of the equation while keeping the constants to the opposite side.

step by step: but in order to solve a quadratic using the square root principle the problem must be in the correct form. To solve a quadratic using the square root principle the quadratic must be in vertex form, a(x – h)2 + k.

This is the “best” method whenever the quadratic equation only contains x2 terms. ...

The general approach is to collect all x2 terms on one side of the equation while keeping the constants to the opposite side

3: 2

step-by-step explanation:

shorter piece is 2: 3, so just reverse it, and you get 3: 2

hope it you

step-by-step explanation:

sin(7pi/6 - pi/3)  

= sin(7pi/6 - 2pi/6)  

= sin(5pi/6)  

= sin(pi - pi/6)  

= sin(pi/6)  

= 1/2  

sin 7pi/6 - sin pi/3  

= sin (pi + pi/6) - sin pi/3  

= -sin pi/6 - sin pi/3  

= -1/2 - sqrt(3)/2  

= -(1+sqrt(3))2