Find an equation of the line that passes through (2,-3) and is perpendicular to the line 2x-y=10.

l#First find the gradient first, remember the formula of equation of the line is y = mx + c where m is the gradient.

2x - y = 10

-y = -2x + 10

y = 2x - 10

#So the gradient is 2, now find the equation of the line

y - y1 = m(x - x1)

y - (-3) = 2(x - 2)

y + 3 = 2x - 4

y = 2x - 4 - 3

y = 2x - 7

2y = x - 7/2

-x + 2y = -7/2

x - 2y = 7/2

there are no answer choices

step-by-step explanation:

the answer would be d.

step-by-step explanation:

move all variables to the left side and all constants to the right side

(x−3)^2+(y−1)^2=16

this is the form of a circle. use this form to determine the center and radius of the circle.

( x − h ) 2 + ( y − k ) 2 = r 2

match the values in this circle to those of the standard form. the variable   r   represents the radius of the circle,   h   represents the x-offset from the origin, and   k   represents the y-offset from origin.

r = 4

h = 3

k = 1

the center of the circle is found at   ( h , k ) .

center:   ( 3 , 1 )

these values represent the important values for graphing and analyzing a circle.

center:   ( 3 , 1 ).

radius:   4