idk man good luck man
answer: 7. if the functions had a negative leading coefficient and is of even degree, which statement about the graph is true?
step-by-step explanation:
6^2 or 36
6000n
6×1000n
6×10^3 n
so we need 6n need to be a perfect cube
so n has to be 6^2 so that 6n is 6^3
what i'm saying is if you let n be 6^2 you have 6^3×10^3 or 60^3 which is a perfect cube