School A has graduated 1,700 students and graduates 50 students every year. School B has graduated 600
students, but graduates 150 every year. How many years (Y)
will it be before School B has as many graduates as School A?

the answer is 11 years

Step-by-step explanation:

if school A is graduated 50/years,

the graduated in 11 years is 550

added of graduated 1,700 in 550 is 2,250

if school B is graduated 150/years,

the graduated in 11 years is 1650

added of graduated 600 in 1650 is 2,250

so School A and B is to be equal in 11 years

false

step-by-step explanation:

4y - 6 + 4y^2 - 9

before simplifying this contains 4 terms

after simplifying

4y -15 + 4y^2

it contains 3 terms