Use complete the square to solve 5x²-7x-3=0

Step-by-step explanation:

ax2 + bx + c = 0

x12 = (-b ± √D) / 2a , D = b2 - 4ac .

5x2 + 7x + 3 = 0

a = 5 , b = 7 , c = 3

D = 49 - 60 = - 11 , x1 = (-7 - i √11) / 10

x2 = (-7 + i √11) / 10

step-by-step explanation:

given that there are two triangles j'k'l' and jkl>

the former is got by dilating the second one.

when drawn on a grid, (graph paper) coordinates of vertices of first triangle is

(6,12)j, (9,6)k and (12,9)l

side jk has length = distance between j and k

=

side j'k'=distance between j' and k'

=

ie j'k'l' has sides 1/3 of that of corresponding sides of jkl.

hence scale factor of 1/3 is used to get j'k'l'from jkl