. ABC is an equilateral triangle of side 3 units. The points P, Q lie on BC, CA respectively and are such that AQ = CP = 2units. If the point R lies on AB produced so that BR = 1unit, prove that P, Q, R are collinear

Points P, Q and R are collinear

Step-by-step explanation:

To prove that two or three points are collinear the slope of any two pairs of point have to be the same

From the given question

AR = AQ = CP = 2 units

BR = BP = CQ =  1 unit

For line AB we have ; AR , BR . hence slope of line = BR / AR = 1/2

For line BC we have ; BP , CP . hence slope of line = CP / BP = 2/1

For Line AC we have ; AQ , CQ . hence slope of line = CQ / AQ = 1/2

 slope of Line AB = slope of Line AC   hence points P, Q and R are collinear

answer: your gay

step-by-step explanation:

you dont know math

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.