Calculate the values of angles A and C of triangle ABC, where b =17.23cm, c=10.86cm and B=10 1 degree 15

C = 38.18°;  A = 40.57°

Step-by-step explanation:

B = 101' 15"

B = 101° + (15/60) = 101 + 0.25 = 101.25°

b =17.23cm,c=10.86cm

From Sine rule :

c/ sin C = b / Sin B

10.86 / sin C = 17.23 / sin 101.25

SinC = (sin 101.25 * 10.86) / 17.23

Sin C = 10.651328 / 17.23

Sin C = 0.6181850

C = Sin^-1(0.6181850)

C = 38.183716

C = 38.18°

Sum of angles in a triangle = 180°

A +  B + C = 180°

A + 101.25° + 38.18° = 180°

A = (180 - (101.25 + 38.18))

A = 40.57°