Use algebra to find the point at which the line h(x)=−(3/5)x+(7/5) intersects the line k(x)=(−8/3)x+(404/45).

the point (3.667, 0.8)

Step-by-step explanation:

We want to find the point at which the lines:

h(x) = -(3/5)*x + (7/5)

and

k(x) = (-8/3)*x + (404/45)

If the lines intersect, then we must have:

h(x) = k(x)

if we write the functions we get:

-(3/5)*x + (7/5) = (-8/3)*x + (404/45)

Now we need to solve this for x.

-(3/5)*x + (8/3)*x = (404/45) - (7/5)

(8/3 - 3/5)*x = 404/45 - 63/45 = 341/45

(40/15 - 9/15)*x = 341/45

(31/15)*x = 341/45

x = (341/45)*(15/31) = 3.667

Now we can input this value of x in the functions to get the output.

h(3.667) = -(3/5)*3.667 + 7/5 = -0.8

Then the point where our points intersect is the point (3.667, 0.8)

so firstly, we need to isolate the y variables to be able to solve these inequalities. firstly, add 0.5x on both sides of the first inequality and subtract 1.5x on both sides of the second inequality:

now since the slope is positive for the first inequality, this means that the line going upwards belongs to the first inequality, and the line going downwards belongs to the second inequality.

next, since y ≥ in the first inequality, this means that the shaded region will be above the first inequality's line, thus shading regions a and b.

next, since y ≤ in the second inequality, this means that the shaded region is going to be below this line, thus shading regions a and c.

since both lines shade region a, this means that region a is the solution.

step-by-step explanation:

mark brainliest!