Students who attend Anytown College pay either in-state or out-of-state tuition, depending on where they reside. The mean and standard deviation of the sum, S, of tuition for a randomly selected pair of in-state and out-of-state students are μS = $6,348.75 and σS = $1,508.48. How can these values be interpreted? Check all that apply. The average of the sums of both types of tuitions would be $6,348.75 for many, many randomly selected pairs of students. Students who pay both types of tuition will pay $6,348.75 per semester. For a pair of randomly selected in- and out-of-state students, the sum of their tuitions is $6,348.75. For a pair of randomly selected in- and out-of-state students, the sum of their tuitions typically varies from the mean of $6,348.75 by about $1,508.48. Students who pay both in- and out-of-state tuition should expect their cost to vary by about $1,508.48 per semester.

For a pair of randomly selected in- and out-of-state students, the sum of their tuition typically varies from the mean of $6,348.75 by about $1,508.48.

Step-by-step explanation:

Given

Required

Interpret the standard deviations

In statistic, standard deviation is a measure of how the given data lies away (or varies) from the mean.

This implies that:

For the in-state students, the standard deviation measures how the sum of their tuition varies from 6348.75

For the out-state students, the standard deviation measures how the sum of their tuition varies from 1508

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1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.