To investigate whether there is a difference in opinion on a certain proposal between two voting districts, A and B, two independent random samples were taken. From district A, 35 of the 50 voters selected were in favor of the proposal, and from district B, 36 of the 60 voters selected were in favor of the proposal. Which of the following is the test statistic for the appropriate test to investigate whether there is a difference in the proportion of voters who are in favor of the proposal between the two districts (district A minus district B)? A. 35-36 A 50 B. 35-36 0.7 0.6 V 50 0 + 60 C. 0.7-0.6 (0..) (.x) (+) 0.7-0.6 D. V(0.7)(0.6) (Hot 50+60 0.7 -0.6 E. (0.7) (0.6) VE 60

C:      t= x1`-x2`/√p^q^(1/n1 +1/n2)

0.7−0.6/(0.65)(0.35)√(1/50+1/60)

Step-by-step explanation:

The options given are

A

35−36/ 35/√50+3660

B

35−36/0.7/√50+0.660

C

0.7−0.6/(0.65)(0.35)√(1/50+1/60)

D

0.7−0.6/(0.7)(0.6)/√(1/50+1/60)

E

0.7−0.6/(0.7)(0.6)/√150+160

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This is a test hypothesis about difference of  means between two proportions.

The test statistic used is

t= x1`-x2`/√p^q^(1/n1 +1/n2)

x1`= 35/50= 0.7

x2`= 36/60= 0.6

so

x1`-x2`

= 35/50-36/60

= 0.7-0.6

p^= 35+36/50+60= 71/110= 0.645= 0.65

q^= 1-p^= 1-0.65= 0.35

p^q^= (0.65) (0.35)

n1= 50 and n2= 60

therefore √1/n1 +1/n2= √1/50+1/60

Now Putting the values in the test statistics we get

t= x1`-x2`/√p^q^(1/n1 +1/n2)

0.7−0.6/√(0.65)(0.35)(1/50+1/60)

Hence C is the correct option

salary

step-by-step explanation:

let m = monomial

let t = trinomial

so, m times t = t.

monomial times a trinomial = another trinomial.