Suppose that X is partitioned into sets X1,X2, and X3. Suppose that n(X) = 72. Suppose that the number of elements in X1 is three times the number in X2 and the number of elements in X2 is twice the number in X3. Find the number of elements in each set X1, X2, and X3.

astronomers is your final answer! : )

area = length x width

length = 2 x width

32 = 2 x width x width

32 = 2 x width^2

36 = width ^2  

width = 6

length = 12

area is 32

perimeter = 2 x 12 + 2 x 6 = 24 + 12 = 36

step-by-step explanation:

don't know what that says sorry i can't you

step-by-step explanation:

idk what it says