If y varies directly as the square root of x and y=3, x=3. calculate y when x=64​

  y = 64√3

Step-by-step explanation:

Step(i):-

Given that the 'y' varies directly as √x

    ⇒ y∝ √x

    ⇒  y = k√x

Put y=3 and x=3

       3 = k ×√3

   √3  k = √3×√3

After cancellation '√3' on both sides, we get

      k = √3

Step(ii):-

   Given that x=64 and k = √3

We have a function   y = k√x ..(i)

substitute x =64 and k = √3 in equation (i)

               y = √3 × 64

             y = 64√3

(x, y)→(x − 8, y − 7)

step-by-step explanation:

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